grep: Remove newlines before matching a line
Otherwise, a pattern with a '$' anchor will never match and POSIX says that "By default, an input line shall be selected if any pattern ... matches any part of the line excluding the terminating <newline>"
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7ed4866556
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1ca8a314f8
7
grep.c
7
grep.c
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@ -129,6 +129,9 @@ grep(FILE *fp, const char *str)
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int match = NoMatch;
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for(n = 1; (len = agetline(&buf, &size, fp)) != -1; n++) {
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/* Remove the trailing newline if one is present. */
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if (len && buf[len - 1] == '\n')
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buf[len - 1] = '\0';
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for(pnode = phead; pnode; pnode = pnode->next) {
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if(regexec(&pnode->preg, buf, 0, NULL, 0) ^ vflag)
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continue;
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@ -146,9 +149,7 @@ grep(FILE *fp, const char *str)
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printf("%s:", str);
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if(mode == 'n')
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printf("%ld:", n);
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printf("%s", buf);
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if(len && buf[len - 1] != '\n')
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putchar('\n');
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puts(buf);
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break;
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}
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match = Match;
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