Correctly handle leftover input
We cannot rely on ungetc() pushing back more than 1 character reliably on all systems, so just note if we have leftover input and process it in the next run.
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1963a7cfb3
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17
xargs.c
17
xargs.c
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@ -14,7 +14,6 @@ enum {
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static int inputc(void);
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static void deinputc(int);
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static void deinputstr(char *);
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static void fillargbuf(int);
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static int eatspace(void);
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static int parsequote(int);
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@ -40,6 +39,7 @@ usage(void)
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int
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main(int argc, char *argv[])
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{
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int leftover;
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long argsz, argmaxsz;
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char *arg;
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int i;
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@ -65,6 +65,7 @@ main(int argc, char *argv[])
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if (!cmd)
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eprintf("malloc:");
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leftover = 0;
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do {
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argsz = 0; i = 0;
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if (argc > 0) {
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@ -77,17 +78,18 @@ main(int argc, char *argv[])
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argsz += strlen(cmd[i]) + 1;
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i++;
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}
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while ((arg = poparg())) {
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while (leftover == 1 || (arg = poparg())) {
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if (argsz + strlen(arg) + 1 > argmaxsz ||
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i >= NARGS - 1) {
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if (strlen(arg) + 1 > argmaxsz)
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enprintf(EXIT_FAILURE, "insufficient argument space\n");
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deinputstr(arg);
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leftover = 1;
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break;
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}
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cmd[i] = strdup(arg);
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argsz += strlen(cmd[i]) + 1;
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i++;
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leftover = 0;
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}
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cmd[i] = NULL;
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if (i == 1 && rflag == 1); else spawn();
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@ -118,15 +120,6 @@ deinputc(int ch)
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ungetc(ch, stdin);
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}
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static void
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deinputstr(char *arg)
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{
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char *p;
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for (p = &arg[strlen(arg) - 1]; p >= arg; p--)
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deinputc(*p);
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}
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static void
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fillargbuf(int ch)
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{
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